【程序4】输入某年某月某日,判断这一天是这一年的第几天?

mac2022-06-30  81

第一种方法:

def is_leap_year(year): if(year % 4 == 0 and year % 100 != 0) or year % 400 == 0: return True else: return False def function1(year,month,day): leap_year = [31,29,31,30,31,30,31,31,30,31,30,31] no_leap_year = [31,28,31,30,31,30,31,31,30,31,30,31] if is_leap_year(year): result = sum(leap_year[:month - 1]) + day else: result = sum(no_leap_year[:month - 1]) +day return result

第二种方法

import datetime day = datetime.date(2016,12,31) print(day.strftime('%j'))

第三种方法

year = int(input('year:')) month = int(input('month:')) day = int(input('day:')) months = (0,31,59,90,120,151,181,212,243,273,304,334) if 0 <= month <= 12: sum = months[month - 1] else: print('data error') sum += day leap = 0 if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)): leap = 1 if (leap == 1) and (month > 2): sum += 1 print('it is the %dth day.' % sum)

转载于:https://www.cnblogs.com/fanren224/p/8457283.html

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