python3+入门小知识整理,直接拷贝运行即可

mac2022-06-30  73

 python3+学习小知识整理,python where循环, python for循环,python 打印参数,python数组求和,python字符串替换等等,后续会持续更新。

#!/usr/bin/env python # -*- coding: utf-8 -*- #where循环 count = 0 while (count<10): print ('Th count is', count) count += 1 print ("down") pass #字符串转移 print(arrayList[-1]) print('\\\n\\') print(r'\\\r\\') #原样输出 print('\n'); print('---------------') print('\\\\') print(r'''hello,\n world''') age = 1 while (age<10): if (age>5): print("now nums=%s" % age) break pass else: print(r'---nums=%s' % age) age+=1 test_array = ['kevin','ruby'] print(len(test_array)) print("len count array is =%s" % len(test_array)) #数组末尾追加操作, append函数 test_array.append('xxxxxxxxxxxxxx') print("python append array param=%s" % test_array) print(test_array) lists = ['name', 'quest', 'favorite color'] print("array list is :%s" % lists) for i in range(len(lists)): print("key is =%s" % i , "value is =%s" % lists[i]) print("---------------------") #循环判断,条件满足调出循环, range 函数 (开始值,结束之,+值/-值) for k in range(1,100,2): if k>20: print("now key is : %s" % k) break pass else: print("----k===%s" % k) print("---------------------") string_1 = "abcdefg" #统计字符串长度 len函数,可统计 array,string 等 print("now string length is %s" % len(string_1), "nums") #字符串循环单个输出 for k in string_1: print("_%s_" % k) print("字符串获取指定某一位的值===",string_1[5]) #从指定位数后面开始替换,保留前面值 print("字符替换函数:",string_1[:4]+'___testok!!!') #从指定位数+1开始替换后面,只保留当前位数+1的值 print("字符替换函数:",string_1[4]+'___xxxxxxxxxxxx!!!') # 判断是否是整数 print(isinstance(111, int))

  

 

转载于:https://www.cnblogs.com/LoveProgram/articles/9566032.html

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