Compare Version Numbers

 

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.The . character does not represent a decimal point and is used to separate number sequences.For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37 public class Solution { public int compareVersion(String version1, String version2) { String[] levels1 = version1.split("\\."); String[] levels2 = version2.split("\\."); int length = Math.max(levels1.length, levels2.length); for (int i=0; i<length; i++) { Integer v1 = i < levels1.length ? Integer.parseInt(levels1[i]) : 0; Integer v2 = i < levels2.length ? Integer.parseInt(levels2[i]) : 0; int compare = v1.compareTo(v2); if (compare != 0) { return compare; } } return 0; } }

split: http://stackoverflow.com/questions/7935858/the-split-method-in-java-does-not-work-on-a-dot

reference: https://leetcode.com/discuss/19118/accepted-small-java-solution

转载于:https://www.cnblogs.com/hygeia/p/5469920.html

相关资源：JAVA上百实例源码以及开源项目