输入一个整数，判断它的奇偶性后输出结果。

1.判断它是否能被2整除。

#include "iostream" using namespace std; int main(){ int input; cout<<"Which number do you want to test?/n"; cin>>input; if(input&1) cout<<"number "<<input<<" is odd."; else cout<<"number "<<input<<" is even."; } 

 

2.判断她的最后一位。（在二进制表示形式中，奇数的末位为1，偶数的末位为0）可以用整数n与1进行按位与运算。

 

#include "iostream" using namespace std; int main(){ int input; cout<<"Which number do you want to test?/n"; cin>>input; if(input&1) cout<<"number "<<input<<" is odd."; else cout<<"number "<<input<<" is even."; } 

转载于:https://www.cnblogs.com/J2EEPLUS/archive/2009/09/07/2487819.html

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