<asp:GridView ID="GridView1" runat="server" OnDataBound="GridView1_DataBound" OnRowDataBound="GridView1_RowDataBound"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:RadioButton ID="RadioButton2" runat="server" GroupName="tester" /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> 是不能实现排斥的 因为radiobutton的排斥在html中实际上就是name值相同的radion会相互排斥 但是在gridview中的radionbutton的name值是会被默认修改为 <input id="GridView1_ctl02_RadioButton2" type="radio" name="GridView1$ctl02$tester" value="RadioButton2" /> name会被改变 = =#
这样可以解决 <asp:GridView ID="GridView1" runat="server" OnDataBound="GridView1_DataBound" OnRowDataBound="GridView1_RowDataBound"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:Label ID="Label2" runat="server" Text="Label"> </asp:Label> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e) { GridViewRow g = e.Row; Label lab=(Label) g.Cells[0].FindControl("Label2"); if (lab != null) { lab.Text = " <input id=/""+lab.ClientID+"/" type=/"radio/" name=/"RadioButton1/" value=/"1/" />"; } }
转载于:https://www.cnblogs.com/J2EEPLUS/archive/2010/03/19/2487935.html
