Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For example: Given the below binary tree,
1
/ \
2 3
Return6.
C++
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
int maxDis;
public:
int maxPathSum(TreeNode *root) {
if(!root){
maxDis=0;
return -1e8;
}
int leftMax=maxPathSum(root->left);
int l=max(0,maxDis);
int rightMax=maxPathSum(root->right);
int r=max(0,maxDis);
maxDis=max(l,r)+root->val;
return max(leftMax,max(rightMax,l+r+root->val));
}
};
转载于:https://www.cnblogs.com/vercont/p/10210291.html