$http.post发的数据,后台取不到两种解决方案

mac2022-06-30  193

方案一:

var url = 'Gulugulus/setMenu', data = { menu: JSON.stringify(menu), test: 'a String' }, transFn = function(data) { return $.param(data);//$.param() 方法创建数组或对象的序列化表示,需引入jquery,或者套用方案二中的部分转换方法进行转换.       }, postCfg = { headers: { 'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}, transformRequest: transFn }; $http.post(url, data, postCfg) .success(function(){ window.location.href = "Gulugulus/subMenu"; });   

  

方案二:   routeApp.config(function($httpProvider) { $httpProvider.defaults.headers.put['Content-Type'] = 'application/x-www-form-urlencoded'; $httpProvider.defaults.headers.post['Content-Type'] = 'application/x-www-form-urlencoded'; // Override $http service's default transformRequest $httpProvider.defaults.transformRequest = [function(data) { /** * The workhorse; converts an object to x-www-form-urlencoded serialization. * @param {Object} obj * @return {String} */ var param = function(obj) { var query = ''; var name, value, fullSubName, subName, subValue, innerObj, i; for (name in obj) { value = obj[name]; if (value instanceof Array) { for (i = 0; i < value.length; ++i) { subValue = value[i]; fullSubName = name + '[' + i + ']'; innerObj = {}; innerObj[fullSubName] = subValue; query += param(innerObj) + '&'; } } else if (value instanceof Object) { for (subName in value) { subValue = value[subName]; fullSubName = name + '[' + subName + ']'; innerObj = {}; innerObj[fullSubName] = subValue; query += param(innerObj) + '&'; } } else if (value !== undefined && value !== null) { query += encodeURIComponent(name) + '=' + encodeURIComponent(value) + '&'; } } return query.length ? query.substr(0, query.length - 1) : query; }; return angular.isObject(data) && String(data) !== '[object File]' ? param(data) : data; }]; });

  

转载于:https://www.cnblogs.com/kms1989/p/5821762.html

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