(字符串 栈) leetcode 921. Minimum Add to Make Parentheses Valid

mac2022-06-30  109

Given a string S of '(' and ')' parentheses, we add the minimum number of parentheses ( '(' or ')', and in any positions ) so that the resulting parentheses string is valid.

Formally, a parentheses string is valid if and only if:

It is the empty string, orIt can be written as AB (A concatenated with B), where A and Bare valid strings, orIt can be written as (A), where A is a valid string.

Given a parentheses string, return the minimum number of parentheses we must add to make the resulting string valid.

 

Example 1:

Input: "())" Output: 1

Example 2:

Input: "(((" Output: 3

Example 3:

Input: "()" Output: 0

Example 4:

Input: "()))((" Output: 4

 

Note:

S.length <= 1000S only consists of '(' and ')' characters.

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这个题是栈的基础题,不过可以用O(n)的时间复杂度和O(1)的空间复杂度来解这个问题。参考题解:https://leetcode.com/articles/minimum-add-to-make-parentheses-valid/

C++代码:

class Solution { public: int minAddToMakeValid(string S) { int ans = 0,bal = 0; for(int i = 0; i < S.size(); i++){ bal += S[i] == '('?1:-1; if(bal == -1){ ans++; bal++; } } return ans+bal; } };

 

转载于:https://www.cnblogs.com/Weixu-Liu/p/10822557.html

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