(JAVA对进制的运算)A + B Again hdu2057要复习

mac2022-06-30  101

(置顶,复习)A + B Again

链接:http://acm.hdu.edu.cn/showproblem.php?pid=2057

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 35905    Accepted Submission(s): 14614

Problem Description There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !  

 

Input The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.  

 

Output For each test case,print the sum of A and B in hexadecimal in one line.  

 

Sample Input +A -A +1A 12 1A -9 -1A -12 1A -AA  

 

Sample Output 0 2C 11 -2C -90  

 

Author linle   注: 此题就是利用Long.parseLong()和Long.toHexString()的 replaceAll("\\+",""),是去除其中的‘+’,因为进制计算不支持带“+”的某一进制的数字字符串,‘-’可以,同时还需要判断正数负数,从而利用Long.toHexString()。   Java代码: import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner inScanner = new Scanner(System.in); while(inScanner.hasNext()) { long l = Long.parseLong(inScanner.next().replaceAll("\\+", ""),16) + Long.parseLong(inScanner.next().replaceAll("\\+", ""),16); if(l<0) { System.out.println("-" + Long.toHexString(-l).toUpperCase()); } else { System.out.println(Long.toHexString(l).toUpperCase()); } } } }

 

 

转载于:https://www.cnblogs.com/Weixu-Liu/p/9674229.html

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