链接：http://acm.hdu.edu.cn/showproblem.php?pid=2163
（此题是为了对于JAVA温故知新的）
Problem Description Write a program to determine whether a word is a palindrome. A palindrome is a sequence of characters that is identical to the string when the characters are placed in reverse order. For example, the following strings are palindromes: “ABCCBA”, “A”, and “AMA”. The following strings are not palindromes: “HELLO”, “ABAB” and “PPA”.Input The input file will consist of up to 100 lines, where each line contains at least 1 and at most 52 characters. Your program should stop processing the input when the input string equals “STOP”. You may assume that input file consists of exclusively uppercase letters; no lowercase letters, punctuation marks, digits, or whitespace will be included within each word.
Output A single line of output should be generated for each string. The line should include “#”, followed by the problem number, followed by a colon and a space, followed by the string “YES” or “NO”.
Sample Input ABCCBA A HELLO ABAB AMA ABAB PPA STOP
Sample Output #1: YES #2: YES #3: NO #4: NO #5: YES #6: NO #7: NO
JAVA代码：
import java.util.Scanner; /** * */ /** * @author lenovo * */ public class Main { /** * @param args */ public static void main(String[] args) { Scanner input = new Scanner(System.in); int i = 1; while(input.hasNextLine()) { String string = input.nextLine(); if(string.equals("STOP")) { break; } else{StringBuffer stringBuffer = new StringBuffer(string); String string2 = stringBuffer.reverse().toString(); if(string2.equals(string)) { # 注意JAVA比较时是用equal（）方法的。 System.out.println("#" + i + ": YES"); } else { System.out.println("#" + i + ": NO"); } i++; } } } }
C++代码：
#include <iostream> #include <string> #include <algorithm> using namespace std; int main() { int T=0; string a; while(cin>>a) { if(a=="STOP") break; T++; string b; b=a; reverse(b.begin(),b.end()); if(b==a) printf("#%d: YES\n",T); else printf("#%d: NO\n",T); } return 0; }
转载于:https://www.cnblogs.com/Weixu-Liu/p/9637626.html
相关资源：JAVA上百实例源码以及开源项目