leetcode原文引用：
Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+ For example, return the following Ids for the above Weather table: +----+ | Id | +----+ | 2 | | 4 | +----+ 我的sql语句如下： select t2.id from Weather t1 inner join Weather t2 on t1.Temperature < t2.temperature and to_days(t1.Date) = to_days(t2.Date)-1 注意：原来忘了使用to_days函数，导致提交一直说有错误，必须要加上to_days函数！！转载于:https://www.cnblogs.com/iamconan/p/7383577.html
