JS解析Url中携带的参数(支持中文)

mac2024-04-15  33

function parseURL(url){ if(!url) return; url = decodeURI(url); var url = url.split("?")[1]; var para = url.split("&"); var len = para.length; var res = {}; var arr = []; for(var i=0;i<len;i++){ arr = para[i].split("="); res[arr[0]] = arr[1]; } return res; } var info = parseURL("https://www.baidu.com?xc_id=196377313325&title=%E4%BD%A0%E5%A5%BD&content=%E5%86%85%E5%AE%B9"); alert(JSON.stringify(info));

完!!!

转自:https://blog.csdn.net/qq_39816586/article/details/87441393

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