删除链表中等于给定值 val 的所有节点。
示例:
输入: 1->2->6->3->4->5->6, val = 6
输出: 1->2->3->4->5
解法1：迭代
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def removeElements(self, head: ListNode, val: int) -> ListNode:
dummy = ListNode(0)
dummy.next = head
prev = dummy
last = prev.next
while last :
if last.val == val:
prev.next = last.next
last = prev.next
else:
prev = prev.next
last = prev.next
return dummy.next
解法2：递归
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def removeElements(self, head: ListNode, val: int) -> ListNode:
if not head: return
head.next = self.removeElements(head.next, val)
return head.next if head.val == val else head
