4.5-3求解数组元素的最小差值

#include <bits/stdc++.h> using namespace std; int f(int a[], int n){ sort(a, a + n); int dmin = a[1] - a[0]; for(int i = 2; i < n; i++){ int temp = a[i] - a[i -1]; if(temp < dmin){ dmin = temp; } } return dmin; } int main(){ int a[] = {4, 3, 1, 2, 5}; int n = sizeof(a) / sizeof(a[0]); cout << "最小差值为:" << f(a, n); return 0; }