猫年,狗年【难度:0级】:
答案1:
public class Dinglemouse {
public static int[] humanYearsCatYearsDogYears(int humanYears
) {
int catYear
= 15 + (humanYears
>= 2 ? 9 + 4 * (humanYears
-2): 0);
int dogYear
= 15+ (humanYears
>= 2 ? 9 + 5 * (humanYears
-2): 0);
return new int[]{humanYears
,catYear
,dogYear
};
}
}
答案2:
public class Dinglemouse {
public static int[] humanYearsCatYearsDogYears(int humanYears
) {
if(humanYears
== 0) return new int[]{0,0,0};
int catYears
= 0, dogYears
= 0;
if(humanYears
== 1)
{
catYears
= 15;
dogYears
= 15;
}
else if(humanYears
== 2)
{
catYears
= 15 + 9;
dogYears
= 15 + 9;
}
else
{
catYears
= 15 + 9 + (humanYears
- 2) * 4;
dogYears
= 15 + 9 + (humanYears
- 2) * 5;
}
return new int[]{humanYears
,catYears
,dogYears
};
}
}
答案3:
public class Dinglemouse {
public static int[] humanYearsCatYearsDogYears(int humanYears
) => humanYears
< 2 ? new int[]{1,15,15} : humanYears
< 3 ? new int[]{2,24,24} : new int[]{humanYears
,24+(humanYears
-2)*4,24+(humanYears
-2)*5};
}
答案4:
public class Dinglemouse {
public static int[] humanYearsCatYearsDogYears(int humanYears
) {
switch(humanYears
)
{
case 1:
return new int[]{1,15,15};
case 2:
return new int[]{2,24,24};
default:
int catYears
= 24;
int dogYears
= 24;
for(int i
= humanYears
-2; i
> 0; i
--)
{
catYears
+= 4;
dogYears
+= 5;
}
return new int[]{humanYears
,catYears
,dogYears
};
}
}
}
答案5:
public class Dinglemouse
{
public static int[] humanYearsCatYearsDogYears(int y
) => y
< 2 ? new[]{1, 15, 15} : new[]{y
, 16+4*y
, 14+5*y
};
}
答案6:
public class Dinglemouse
{
public static int[] humanYearsCatYearsDogYears(int humanYears
)
{
switch (humanYears
)
{
case 1: return new[] {1, 15, 15};
case 2: return new[] {2, 24, 24};
default: return new[] {humanYears
, (humanYears
- 2) * 4 + 15 + 9, (humanYears
- 2) * 5 + 15 + 9};
}
}
}
答案7:
public class Dinglemouse {
public static int[] humanYearsCatYearsDogYears(int humanYears
) =>
new int[]{humanYears
,(humanYears
+ 3)*4 + (humanYears
> 1 ? 5 : 0) -1 ,(humanYears
+ 2)*5 + (humanYears
> 1 ? 4 : 0)};
}
答案8:
public class Dinglemouse
{
public static int[] humanYearsCatYearsDogYears(int humanYears
)
{
int commonAdd
= humanYears
== 1 ? 15 : humanYears
>= 2 ? 24: 0;
int catYears
= commonAdd
;
int dogYears
= commonAdd
;
if (humanYears
> 2)
{
for (int i
= 3; i
<= humanYears
; i
++)
{
catYears
+= 4;
dogYears
+= 5;
}
}
return new int[]{humanYears
,catYears
,dogYears
};
}
}
答案9:
using System
.Collections
.Generic
;
using System
.Linq
;
public class Dinglemouse
{
public static int[] humanYearsCatYearsDogYears(int humanYears
)
{
return new int[]
{
humanYears
,
CatYears().Take(humanYears
).Sum(),
DogYears().Take(humanYears
).Sum()
};
}
static IEnumerable
<int> CatYears()
{
yield return 15;
yield return 9;
while (true)
{
yield return 4;
}
}
static IEnumerable
<int> DogYears()
{
yield return 15;
yield return 9;
while (true)
{
yield return 5;
}
}
}
答案10:
public class Dinglemouse
{
public static int[] humanYearsCatYearsDogYears(int humanYears
)
{
int catAge
= (humanYears
== 1) ? 15 : (humanYears
== 2) ? 24 : 24 + ((humanYears
- 2) * 4);
int dogAge
= (humanYears
== 1) ? 15 : (humanYears
== 2) ? 24 : 24 + ((humanYears
- 2) * 5);
return new int[] { humanYears
, catAge
, dogAge
};
}
}
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