效果: f ( x ) = { x = cos ( t ) y = sin ( t ) z = x y f(x)=\left\{ \begin{aligned} x & = \cos(t) \\ y & = \sin(t) \\ z & = \frac xy \end{aligned} \right. f(x)=⎩⎪⎪⎨⎪⎪⎧xyz=cos(t)=sin(t)=yx
效果: F = { F L 0 < S L F L ∗ S L ≤ 0 < S M F R ∗ S M ≤ 0 < S R F R S R ≤ 0 F=\left\{ \begin{array}{rcl} F_L & & {0 < S_L}\\ F^*_L & & {S_L \leq 0 < S_M}\\ F^*_R & & {S_M \leq 0 < S_R}\\ F_R & & {S_R \leq 0} \end{array} \right. F=⎩⎪⎪⎨⎪⎪⎧FLFL∗FR∗FR0<SLSL≤0<SMSM≤0<SRSR≤0
效果: f ( x ) = { 0 x=0 1 x!=0 f(x)= \begin{cases} 0& \text{x=0}\\ 1& \text{x!=0} \end{cases} f(x)={01x=0x!=0
效果: { a = 100 \left\{ a=100 \right. {a=100 注:此方法可解决多行公式的括号匹配问题
可以自动控制不同层次括号的大小,\left 放在左边括号前面,\right 放在右边括号前面,需要配对使用。(但是和别的括号匹配也行,和\right.匹配也行) ( ( ( z x l ) ) 1 b ] \left(\left(\left(zxl\right)\right)\frac{1}{b}\right] (((zxl))b1]
不需要成对使用
\Bigg ( \bigg [ \Big \{ \big \langle \left | \| x \| \right | \big \rangle \Big \} \bigg ] \Bigg )效果: ( [ { ⟨ ∣ ∥ x ∥ ∣ ⟩ } ] ) \Bigg ( \bigg [ \Big \{ \big \langle \left | \| x \| \right | \big \rangle \Big \} \bigg ] \Bigg ) ([{⟨∣∥x∥∣⟩}])
欢迎交流和指正!