LinkedList Api详解

mac2025-06-17  10

package collectionApi; import java.util.Iterator; import java.util.LinkedList; import java.util.ListIterator; public class LinkedListApi { public static void main(String[] args) { LinkedList<String> linkedList = new LinkedList<>(); linkedList.add("D"); linkedList.add("E"); linkedList.add("G"); linkedList.add("A"); linkedList.add("H"); System.out.println(linkedList); //[D, E, G, A, H] LinkedList<String> linkedList2 = new LinkedList<>(linkedList); // String key; key = linkedList.getFirst(); // 取表头 key = linkedList.getLast(); // 取表尾 key = linkedList.get(2); // 取index = 2 key = linkedList.peek(); // 取表头 key = linkedList.peekFirst(); // 取表头 key = linkedList.peekLast(); // 取表尾 boolean b = linkedList.remove("G"); // 删除第一个给定元素 删除返回true key = linkedList.remove(3); // 删除index = 3 返回删除元素 key = linkedList.remove(); // 删除表头 返回删除元素 key = linkedList.removeFirst(); // 删除表头 返回表头 key = linkedList.removeLast(); // 删除表尾返回表尾 key = linkedList.poll(); // 删除表头返回 表头 key = linkedList.pollFirst(); // 删除表头返回 表头 key = linkedList.pollLast(); // 删除表尾 返回表尾 linkedList.push("44"); // addFirst linkedList.addFirst("3"); // 表头增加元素 linkedList.addLast("7"); // 表尾增加元素 b = linkedList.contains("E"); // 包含返回true int n = linkedList.size(); // 元素count b = linkedList.addAll(linkedList2); // 返回true System.out.println(linkedList); // [3, 44, 7, D, E, G, A, H] b = linkedList.addAll(3, linkedList2); // 从index = 3 增加 System.out.println(linkedList); //linkedList.clear(); 清空 key = linkedList.set(4, "EE"); // 设定指定index 的值 System.out.println(key); b = linkedList.offer("3"); // add b = linkedList.offerFirst("77"); //addFirst b = linkedList.offerLast("22"); // addLast b = linkedList.removeFirstOccurrence("E"); // remove("E") b = linkedList.removeLastOccurrence("3"); // 删除最后一个 n = linkedList.indexOf("E"); // 第一次出现的位置index n = linkedList.lastIndexOf("G"); // 第后一次出现的位置index System.out.println(linkedList); // [77, 3, 44, 7, D, EE, G, A, H, D, G, A, H, 22] ListIterator<String> listIterator = linkedList.listIterator(4); // 正向迭代器 while (listIterator.hasNext()) { String string = listIterator.next(); //System.out.println(string); //D, EE, G, A, H, D, G, A, H, 22] } Iterator<String> iterator = linkedList.descendingIterator(); // 反向迭代器 while (iterator.hasNext()) { String string = iterator.next(); //System.out.println(string); //22, H, A, G,D,H,A... } Object[] objects = linkedList.toArray(); // 转为对象数组 String[] strings = new String[1]; strings = linkedList.toArray(strings); // 转为数组 Object object = linkedList.clone(); // 浅表克隆 linkedList.add(3, "EE"); System.out.println(linkedList); } }
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