数据库数据删除重复数据

mac2025-08-30  26

-- --标准sql方法:mysql、sql server-- -- 查询重复 方法一 select t.id,t.name from test t join(     select min(id) id,name from test group by name having(count(1)>1) ) tt on t.id>tt.id and t.name=tt.name   -- 查询重复 方法二 select * from test  where exists(     select * from (         select min(id) id,name from test group by name having(count(1)>1)     ) as tt where test.id>tt.id and test.name=tt.name )     -- 删除重复 方法  delete from test  where exists(     select * from (         select min(id) id,name from test group by name having(count(1)>1)     ) as tt where test.id>tt.id and test.name=tt.name )     -- --sql server方法---- -- 查询 select * from (     select ROW_NUMBER() over(partition by name order by id ) row,id,name from test  ) t where t.row>1     -- 删除 delete from test  where exists(     select * from      (         select ROW_NUMBER() over(partition by name order by id ) row,id,name from test      ) t where t.row>1 and test.id=t.id )

 

————————————————————————————————————————————

在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断  select * from people  where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录  delete from people  where   peopleName in (select peopleName    from people group by peopleName      having count(peopleName) > 1)  and   peopleId not in (select min(peopleId) from people group by peopleName     having count(peopleName)>1) 

3、查找表中多余的重复记录(多个字段)  select * from vitae a  where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录  delete from vitae a  where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)  and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) 

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录  select * from vitae a  where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)  and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)   

6.消除一个字段的左边的第一位:

update tableName set [Title]=Right([Title],(len([Title])-1)) where Title like '村%'

7.消除一个字段的右边的第一位:

update tableName set [Title]=left([Title],(len([Title])-1)) where Title like '%村'

8.假删除表中多余的重复记录(多个字段),不包含rowid最小的记录  update vitae set ispass=-1 where peopleId in (select peopleId from vitae group by peopleId

最新回复(0)