先占个坑, 以后来写讲解

代码实现

求解 f(x)=x^5+2x-1 = 0的解

#include <iostream> #include <cmath> using namespace std; // newtown method double newtown(double (*fun)(double x), double (*deriv)(double x), double x0, double threshold) { while (abs(0 - fun(x0)) > threshold) { x0 -= fun(x0) / deriv(x0); } return x0; } // main int main(int argc, char const *argv[]) { double x0 = 0, threshold = 0.0002; auto fun = [](double x) -> double { return pow(x, 5.0) + 2 * x - 1; }; auto deriv = [](double x) -> double { return 5 * pow(x, 4.0) + 2; }; double res = newtown(fun, deriv, x0, threshold); cout << res << endl; cout << 18.0 / 37.0 << endl; }