f ′ ( x ) = y f^{'}(x)=y f′(x)=y 即 ( x l o g x ) ′ = y , l o g x + 1 = y , x = e y − 1 (xlogx)^{'}=y,logx+1=y,x=e^{y-1} (xlogx)′=y,logx+1=y,x=ey−1
https://www.jianshu.com/p/ccdc504d6f9e