1 package com.array.jun;
2
3 import java.util.Arrays;
4 import java.util.Scanner;
5
6 public class ArrayTest {
7
8 public static int[] arrayname0;
//定义数组
9 public static int[] arrayname1 = {0,0,0,0,0
};
10 public static int[] arrayname2 =
new int[]{1,2,3,4,5,6};
//静态数组初始化
11 public static int[] arrayname3 =
new int[10];
//动态数组初始化
12
13 public static void arrayTest1(){
14 for (
int i : arrayname1) {
15 System.out.print(arrayname1[i] + " ");
//foreach遍历第一个静态初始化数组没问题，第二种会抛出数组越界异常
16 }
17 System.out.println();
18 for (
int i = 0; i < arrayname2.length; i++
) {
19 System.out.print(arrayname2[i] + " ");
//for遍历都没问题
20 }
21 System.out.println("\n" + arrayname2[1
]);
22 }
23
24 public static void arrayTest2() {
//测试数组静态工具类方法
25 System.out.println(Arrays.binarySearch(arrayname2, 3
));
26 System.out.println(Arrays.binarySearch(arrayname2, 2, 4, 3));
//按值索引 binarySearch(a, fromIndex, toIndex, key)
27 int[] array_b = Arrays.copyOf(arrayname2, 4
);
28 // int[] array_b = Arrays.copyOfRange(arrayname2, 2, 5); //数组元素复制
29 System.out.println(Arrays.toString(array_b));
//tostring
30 System.out.println(Arrays.equals(array_b, arrayname1));
//equals比较相等
31 Arrays.fill(arrayname3, 4);
//填充
32 System.out.println(Arrays.toString(arrayname3));
33 Arrays.sort(arrayname2);
//排序
34 }
35
36 public static void test(){
//测试方法，方便回调
37 Scanner scan =
new Scanner(System.in);
38 switch (scan.nextInt()) {
39 case 0
:
40 arrayTest1();
41 break;
42 case 1
:
43 arrayTest2();
44 break;
45 default:
46 {
47 System.out.println("请重新输入！"
);
48 test();
49 }
50 break;
51 }
52 }
53
54 public static void main(String[] args) {
55 // TODO Auto-generated method stub
56 test();
57 }
58
59 }
案例：
1 package com.array.jun;
2
3 import java.util.Scanner;
4 /**
5 *
6 * @author pengjun
7 * @version 1.0
8 * 完成一个数字金额转换成人民币读法的工具！
9 */
10 public class SwitchTools {
11
12 private static String[] hanzi = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"
};
13 private static String[] unit = {"十","佰","千","万"
};
14
15 /**
16 * @param num 需要被分解的浮点数
17 * @param zheng 整数部分
18 * @param xiao 小数部分
19 * @return 返回一个含整数和小数字符串数组
20 */
21 public static String[] getNum(
double num){
22 long zheng = (
long)num;
23 long xiao = (
long)Math.round((num - zheng) * 100
);
24 return new String[]{zheng + ""
,String.valueOf(xiao)};
25 }
26
27 /**
28 * @param stringNum 被分解的字符串数组
29 * @param numLen0 整数长度
30 * @param numLen1 小数长度
31 * @return result 拼接字符串
32 */
33 public static String readNum(String[] stringNum){
34 String result = ""
;
35 int numLen0 = stringNum[0
].length();
36 for (
int i = 0; i < numLen0; i++
) {
37 int num0 = stringNum[0].charAt(i) - 48
;
38 if (i != numLen0 - 1 && num0 != 0
) {
39 result += hanzi[num0] + unit[numLen0 - i - 2
];
40 }
else {
41 result +=
hanzi[num0];
42 }
43 }
44
45 result += "点"
;
46 int numLen1 = stringNum[1
].length();
47 for (
int j = 0; j < numLen1; j++
) {
48 int num1 = stringNum[1].charAt(j) - 48
;
49 result +=
hanzi[num1];
50 }
51
52 return result;
53 }
54
55 public static void test(){
56 Scanner scan =
new Scanner(System.in);
57 double num =
scan.nextDouble();
58 System.out.println(readNum(getNum(num)));
59 }
60
61 public static void main(String[] args) {
62 // TODO Auto-generated method stub
63 test();
64 }
65
66 }
