扫雷游戏 > > 1. 第一次下子，不炸死。> 2. 坐标周围没雷，可以实现展开。

题目

扫雷游戏

第一次下子，不炸死。坐标周围没雷，可以实现展开。

这种题型考验的还是思路与工程能力，代码不难，慢慢来。

先做头文件 < 我用的VS2019编译器 >

#ifndef __GAME_H_ #define __GAME_H_ #include<stdio.h> #include<string.h> #pragma warning(disable:4996) #define COL 12 #define ROW 12 #define NUM 20 void start(); int statistics(char mine_table[COL][ROW], int x, int y); void showtable(char show_table[COL][ROW], int col, int row); void setmine(char mine_table[COL][ROW], int col, int row, int* no_x, int* no_y); void Expand(char mine_table[COL][ROW], char show_table[COL][ROW], int x, int y); #endif // !__GAME_H_

接着就输入主函数`

#include"game.h" void start() { printf("###########################\n"); printf("### Welcome to come here###\n"); printf("###########################\n"); printf("#### 1.play 0.exit #####\n"); printf("###########################\n"); } int main() { start(); int ch = 0; int choose = 0; while (!ch) { printf("Please choose:>"); scanf("%d", &choose); switch (choose) { case 1: game(); break; case 0: ch = 1; break; default: printf("enter error, please enter again!\n"); break; } } printf("ByeBye!!\n"); return 0; }

然后就是其他功能函数

#include"game.h" void game() { char mine_table[COL][ROW]; char show_table[COL][ROW]; int no_x, no_y; memset(mine_table, '0', sizeof(mine_table)); memset(show_table, '*', sizeof(show_table)); setmine(mine_table,COL,ROW, &no_x, &no_y); int x = 0, y = 0; int times = 100 - NUM; do { system("cls"); showtable(show_table, COL, ROW); printf("Please enter your coord:>"); scanf("%d%d", &x, &y); if (x < 1 || x>10 || y < 1 || y>10) { printf("enter orrer! Please enter again\n"); continue; } if (show_table[x][y]!='*') { printf("enter orrer! it has used! Please enter again\n"); continue; } if (mine_table[x][y] == '1') { if (times == 80) { mine_table[x][y] = '0'; mine_table[no_x][no_y] = '1'; } else { printf("Game Over!!\n"); showtable(mine_table, COL, ROW); break; } } show_table[x][y] = statistics(mine_table, x, y)+'0'; Expand(mine_table, show_table, x, y); times--; } while (times > 0); printf("Are you again?\n"); start(); } void setmine(char mine_table[COL][ROW], int col, int row,int* no_x, int* no_y) { int num = NUM; srand((unsigned)time(NULL)); while (num) { int x = rand() % (col - 2) + 1; int y = rand() % (row - 2) + 1; if (mine_table[x][y] == '0') { mine_table[x][y] = '1'; num--; } } for (int i = 1; i <= 10; i++) { for (int j = 1; j <= 10; j++) { if (mine_table[i][j] == '0') { no_x = i; no_y = j; return; } } } } void showtable(char show_table[COL][ROW], int col, int row) { printf(" "); for (int i = 1; i <= 10; i++) { printf(" %2d |", i); } printf("\n"); for (int i = 1; i <= 11; i++) { printf("-----"); } printf("\n"); for (int i = 1; i <= 10; i++) { printf("%2d |", i); for (int j = 1; j <= 10; j++) { printf(" %2c |", show_table[i][j]); } printf("\n"); for (int i = 1; i <= 11; i++) { printf("-----"); } printf("\n"); } } int statistics(char mine_table[COL][ROW], int x, int y) { return mine_table[x - 1][y - 1] + mine_table[x - 1][y] + mine_table[x - 1][y + 1] + mine_table[x][y - 1] \ + mine_table[x][y + 1] + mine_table[x + 1][y - 1] + mine_table[x + 1][y] + mine_table[x + 1][y + 1] - 8 * '0'; } void Expand(char mine_table[COL][ROW], char show_table[COL][ROW],int x, int y)//展开函数 { if (x>0&&x<11&&y>0&&y<11) { if (statistics(mine_table, x, y) + '0' == '0') //周围没有雷 { show_table[x][y] = ' '; //置为空白 if (show_table[x - 1][y - 1] == '*') { Expand(mine_table, show_table, x - 1, y - 1); } if (show_table[x - 1][y] == '*') { Expand(mine_table, show_table, x - 1, y); } if (show_table[x - 1][y + 1] == '*') { Expand(mine_table, show_table, x - 1, y + 1); } if (show_table[x][y - 1] == '*') { Expand(mine_table, show_table, x, y - 1); } if (show_table[x][y + 1] == '*') { Expand(mine_table, show_table, x, y + 1); } if (show_table[x + 1][y - 1] == '*') { Expand(mine_table, show_table, x + 1, y - 1); } if (show_table[x + 1][y] == '*') { Expand(mine_table, show_table, x + 1, y); } if (show_table[x + 1][y + 1] == '*') { Expand(mine_table, show_table, x + 1, y + 1); } } } }