二分图匹配问题 再理解+面向对象模板

mac2026-02-18  9

文章目录

匈牙利算法Kuhn_Munkres

最大匹配:二分图中边集的数目最大的那个匹配;

最小顶点覆盖:用最少的点,让每条边都至少和其中一个点关联;

最小边覆盖:用尽量少的不相交简单路径覆盖有向无环图(DAG)G的所有顶点;

最大独立集:在N个点的图G中选出m个点,使这m个点两两之间没有边的点中,m的最大值。

匈牙利算法

class Hungary { public: static const int MAXN = 1e5+100; static const int MAXM = 2e5+10; struct EDGE { int v, to; }e[MAXM]; int head[MAXM], cnt = 0; inline void add ( int u, int v ) { e[cnt].v = v, e[cnt].to = head[u]; head[u] = cnt++; } int n, ans; int link[MAXN]; bool use[MAXN]; Hungary ( ) { }; Hungary ( int _n ) : n(_n) { }; void ini ( int n ) { this->n = n; cnt = 0; memset( head, -1, sizeof(head) ); } private: bool dfs ( int u ) { for ( int k = head[u]; k != -1; k = e[k].to ) { int v = e[k].v; if ( use[v] ) continue; use[v] = true; if ( link[v] == -1 || dfs ( link[v] ) ) { link[v] = u; return true; } } return false; } public: int run ( ) { ans = 0; memset ( link, 255, sizeof ( link ) ); for ( int i = 0; i < n; ++i ) { memset ( use, 0, sizeof ( use ) ); if ( dfs ( i ) ) ++ans; } return ans; } }h;

Kuhn_Munkres

class Kuhn_Munkres { public: static const int MAXN = 310; static const int INF = 0x3f3f3f3f; int n; int graph[MAXN][MAXN]; bool visx[MAXN], visy[MAXN]; int lx[MAXN], ly[MAXN], match[MAXN], slack[MAXN]; Kuhn_Munkres ( ) { }; Kuhn_Munkres ( int _n ) : n(_n) { }; inline void add ( int u, int v, int w ) { graph[u][v] = w; } inline void ini ( int n ) { this->n = n; memset( graph, 0, sizeof(graph) ); } bool dfs ( int x ) { visx[x] = true; for ( int i = 1; i <= n; i++ ) { if ( visy[i] ) continue; int temp = lx[x] + ly[i] - graph[x][i]; if ( temp == 0 ) { visy[i] = true; if ( match[i] == -1 || dfs ( match[i] ) ) { match[i] = x; return true; } } else if ( slack[i] > temp ) slack[i] = temp; } return false; } long long run ( ) { memset ( match, -1, sizeof ( match ) ); memset ( ly, 0, sizeof ( ly ) ); int i, j, k; for ( i = 1; i <= n; i++ ) for ( j = 1, lx[i] = -INF; j <= n; j++ ) if ( graph[i][j] > lx[i] ) lx[i] = graph[i][j]; for ( i = 1; i <= n; i++ ) { memset ( slack, 0x3f, sizeof ( slack ) ); while ( 1 ) { memset ( visx, 0, sizeof ( visx ) ); memset ( visy, 0, sizeof ( visy ) ); if ( dfs ( i ) ) break; int temp = INF; for ( k = 1; k <= n; k++ ) if ( !visy[k] && temp > slack[k] ) temp = slack[k]; for ( j = 1; j <= n; j++ ) if ( visx[j] ) lx[j] -= temp; for ( int j = 1; j <= n; j++ ) if ( visy[j] ) ly[j] += temp; else slack[j] -= temp; } } long long ans = 0; for ( int i = 1; i <= n; i++ ) ans += graph[match[i]][i]; return ans; } }km;
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