简单有趣#301:跳绳游戏【难度:2级】:

答案1:

def tiaosheng(a): j, t = 0, 0 for j in a: t += 3 if j + t > 60: return min(j, 60-t+3) return 60-t​

答案2:

def tiaosheng(failed_counter): count = 0 jumps = 0 while count < 60: count += 1 jumps += 1 if jumps in failed_counter: count += 3 return jumps​

答案3:

def tiaosheng(fails): return 60 - sum(1 for i, f in enumerate(fails) for k in range(3) if 3*i + f + k < 60)​

答案4:

def tiaosheng(failed_counter): n = 60 for c in failed_counter: if c <= n: n -= min(3, n-c) return n​

答案5:

def tiaosheng(failed_counter): jump = 60 for failed in failed_counter: if failed < jump: jump -= min(jump - failed, 3) return jump​

答案6:

tiaosheng=t=lambda a,e=0:a[0]+e+3>60and min(a[0],60-e)or t(a[1:],e+3)if a else 60-e​

答案7:

def tiaosheng(failed_counter): time = 0 for i in range(1, 61): if time >= 60: return i-1 time += 1 if i in failed_counter: time += 3 return i​

答案8:

def tiaosheng(failed_counter): jumps, fails = [], set(failed_counter) for i in range(1, 61): if i in fails: jumps += [i]*3 jumps.append(i) return jumps[59]​

答案9:

def tiaosheng(failed_counter): total_jump,total_time=0,0 for jump_intervals in [i if index==0 else failed_counter[index]-failed_counter[index-1]for index,i in enumerate(failed_counter)]+[60]: for jump in range(jump_intervals): # Jumping time total_jump+=1 total_time+=1 if total_time==60: return total_jump for intervale in range(3): # Tidying up total_time+=1 if total_time==60: return total_jump​

答案10:

def tiaosheng(failed_counter): timeElapsed = [f + i * 3 for i, f in enumerate(failed_counter)] answer = 60 for t in timeElapsed: if t <= 57: answer -= 3 elif t == 58: answer -= 2 elif t == 59: answer -= 1 return answer​

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