价格芒果【难度:0级】:

答案1:

def mango(quantity, price): return (quantity - quantity // 3) * price​

答案2:

def mango(quantity, price): return (quantity - (quantity//3)) * price​

答案3:

def mango(quantity, price):return ((quantity-(quantity//3))*(price))​

答案4:

def mango(quantity, price): return ((quantity - (quantity // 3)) * price)​

答案5:

def mango(quantity, price): return (quantity - quantity//3)*price;​

答案6:

def mango(quantity, price): return ((quantity - int(quantity/3)) * price)​

答案7:

def mango(quantity, price): return (quantity - int(quantity/3)) * price​

答案8:

def mango(quantity, price): pass return (quantity - int(quantity / 3) ) * price​

答案9:

mango = lambda q,p: p*(q-q//3)​

答案10:

def mango(quantity, price): a, b = divmod(quantity, 3) return price * (a * 2 + b)​

答案11:

def mango(quantity, price): batch = quantity//3 total = (batch * 2 + quantity%3 ) * price return total​

答案12:

def mango(quantity, price): return price * (quantity - (quantity // 3))​

答案13:

def mango(quantity, price): return price * (quantity - quantity // 3)​

答案14:

def mango(quantity, price): print(quantity) return (quantity-quantity//3)*price​

答案15:

def mango(quantity, price): return ((quantity/ 3) * (2 * price)) + (quantity % 3 * price)​

答案16:

def mango(quantity, price): return (quantity / 3 * 2 * price) + quantity % 3 * price​

答案17:

def mango(quantity, price): return quantity / 3 * 2 * price + quantity % 3 * price​

答案18:

from math import ceil; mango=lambda q, p: ceil(q/3*2)*p​

答案19:

mango = lambda q, p: (q // 3 * 2 + q % 3) * p;​

答案20:

mango = lambda q,p: (q//3*2 + q%3)*p​

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