Problem Description:
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element always exist in the array.
Example 1:
Input: [3,2,3] Output: 3Example 2:
Input: [2,2,1,1,1,2,2] Output: 2Analysis:
本题的思路也比较简单,因为队列中最多的元素的个数大于队列长度的一半,因此维护一个变量用来记录队列中多次出现的变量。
Code:
class Solution { public int majorityElement(int[] nums) { int prev = nums[0]; int cnt = 1; for(int i = 1; i < nums.length; i++) { if(nums[i] != prev) { cnt--; } else if(nums[i] == prev) { cnt++; } if(cnt <= 0) { prev = nums[i]; cnt = 1; } } return prev; } }
