获取url上参数

export const getUrlQuery = (name, url) => { if (!url) { url = window.location.href; } name = name.replace(/[[]]/g, '\KaTeX parse error: Expected 'EOF', got '&' at position 1: &̲'); const reg…{name}(=([^&#]*)|&|#|$)`), results = regex.exec(url); if (!results) return null; if (!results[2]) return ‘’; return decodeURIComponent(results[2].replace(/+/g, ’ ')); };