Ajax中获取Json的list集合后进行遍历读取并显示的实例

mac2022-06-30  38

对于json数据的遍历有以下两种方式

var person = {"name": "张三", age: 23, 'gender': true}; var ps = [{"name": "张三", "age": 23, "gender": true}, {"name": "李四", "age": 24, "gender": true}, {"name": "王五", "age": 25, "gender": false}]; //获取person对象中所有的键和值 //for in 循环 for(var key in person){ //这样的方式获取不行。因为相当于 person."name" //alert(key + ":" + person.key); alert(key+":"+person[key]); } //获取ps中的所有值 for (var i = 0; i < ps.length; i++) { var p = ps[i]; for(var key in p){ alert(key+":"+p[key]); } }

在这里我就使用第一种方式

步骤:

创建一个servlet,,用于将要list发送到前台页面中(这里的list我是读取数据库中的数据,Application是一个对象类,里面包含了name,mian等属性) @WebServlet("/getAllServlet") public class getAllServlet extends HttpServlet { protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.setCharacterEncoding("utf-8"); UserDaoImpl dao = new UserDaoImpl(); List<Application> list = dao.apply_list(); System.out.println(list); ObjectMapper mapper = new ObjectMapper(); response.setContentType("application/json;charset=utf-8"); mapper.writeValue(response.getOutputStream(),list); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { this.doPost(request, response); } } 在前台创建一个html文件,并通过ajax的get方法来接受servlet发送的list集合,并进行遍历读取并显示在页面上 <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>显示</title> <script src="js/jquery-2.1.0.min.js"></script> <script> $(function () { $.get("getAllServlet",{},function (data) { var i=1; for(var list in data){ $("#"+i+"_div").html(data[list].main); $("#"+i+"_span").html(data[list].name); i++; } }) }) </script> </head> <body> <span id="1_span"></span> <div id="1_div"> </div> <hr> <span id="2_span"></span> <div id="2_div"> </div> <hr> <span id="3_span"></span> <div id="3_div"> </div> </body> </html>

结果显示页面如下 其中我设置List集合基本内容是: [Application{id=1, name=‘张三’, main=‘软件工程’}, Application{id=21, name=‘王五’, main=‘计算机科学与技术’}, Application{id=22, name=‘赵六’, main=‘金融学’,}]

最新回复(0)