C# 根据年月获得此月第一天和最后一天，并计算工作日

string str = "2015年3月"; int firstIndex = str.IndexOf("年", 0); int secondIndex = str.IndexOf("月", firstIndex + 1); string month = str.Substring(firstIndex + 1, secondIndex - firstIndex - 1); string year = str.Substring(0, 4); DateTime dt = DateTime.Now; string[] time = dt.ToString().Split(new char[]{'/'}); string date = year + "/" + month + "/" + time[2]; DateTime first = Convert.ToDateTime(date).AddDays(1 - Convert.ToDateTime(date).Day); DateTime last=Convert.ToDateTime(date).AddDays(1 - Convert.ToDateTime(date).Day).AddMonths(1).AddDays(-1); //The first day of the month Label1.Text = first.ToString(); //The last day of the month Label2.Text = last.ToString(); //businessDays of the month(except on the weekend) Label3.Text = getint(first, last).ToString();

 

getint 方法：

public int getint(DateTime firstDay, DateTime lastDay) { firstDay = firstDay.Date; lastDay = lastDay.Date; if (firstDay > lastDay) throw new ArgumentException("Incorrect last day " + lastDay); TimeSpan span = lastDay - firstDay; int businessDays = span.Days + 1; int fullWeekCount = businessDays / 7; // find out if there are weekends during the time exceedng the full weeks if (businessDays > fullWeekCount * 7) { // we are here to find out if there is a 1-day or 2-days weekend // in the time interval remaining after subtracting the complete weeks int firstDayOfWeek = firstDay.DayOfWeek == DayOfWeek.Sunday ? 7 : (int)firstDay.DayOfWeek; int lastDayOfWeek = lastDay.DayOfWeek == DayOfWeek.Sunday ? 7 : (int)lastDay.DayOfWeek; if (lastDayOfWeek < firstDayOfWeek) lastDayOfWeek += 7; if (firstDayOfWeek <= 6) { if (lastDayOfWeek >= 7)// Both Saturday and Sunday are in the remaining time interval businessDays -= 2; else if (lastDayOfWeek >= 6)// Only Saturday is in the remaining time interval businessDays -= 1; } else if (firstDayOfWeek <= 7 && lastDayOfWeek >= 7)// Only Sunday is in the remaining time interval businessDays -= 1; } // subtract the weekends during the full weeks in the interval businessDays -= fullWeekCount + fullWeekCount; return businessDays; }

 

转载于:https://www.cnblogs.com/Tinoloving/p/4682887.html

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