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ASP.NET(ASPX)页面获取form表单提交元素的值

mac2022-06-30  32
html知识，Request.Form 接收的是Name值，而非ID值 若是用aspx页面取值，表单中的runat="server"要去掉。 asp.net知识，asp.net的控件的ID和Name值是一样第，但是其在客户端表现是control.clientID而非 control.ID asp.net本身也是可以跨页提交滴，如果是使用自己带的跨页提交就不存在上述问题，不过asp.net自己带的跨页提交有另外的接 收方式

实例

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd "> <html xmlns=" http://www.w3.org/1999/xhtml " > <head>     <title>无标题页</title> </head> <body>     <form id="formPost" action="Default.aspx" method="post">         <div>             <input name="txtPostValue" type="text" />             <input type="submit" /><br />             <br />             <br />             <br />             <input name="filePic" type="file" /></div>     </form>

</body> </html>

 

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd ">

<html xmlns=" http://www.w3.org/1999/xhtml " > <head runat="server">     <title>无标题页</title> </head> <body>     <form id="form1" runat="server">     <div></div>     </form> </body> </html>

using System; using System.Data; using System.Configuration; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.Diagnostics;

public partial class _Default : System.Web.UI.Page {     protected void Page_Load(object sender, EventArgs e)     {         if (!IsPostBack)         {             string str = Request.Form["txtPostValue"].ToString();             string file = Request.Form["filePic"].ToString();

            Response.Write("文本框的值为：" + str + "<br/>");             Response.Write("上传文件的路径为：" + file);         }     } }

转载于:https://www.cnblogs.com/deepwishly/archive/2010/01/31/2551314.html

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