Problem:
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
Summary:
判断数组中是否出现重复值。
Analysis:
1. 给数组排序后遍历，判断相邻两值是否相等。
1 class Solution { 2 public: 3 bool containsDuplicate(vector<int>& nums) { 4 int len = nums.size(); 5 6 sort(nums.begin(), nums.end()); 7 for (int i = 1; i < len; i++) { 8 if (nums[i] == nums[i - 1]) { 9 return true; 10 } 11 } 12 13 return false; 14 } 15 };2. Hash表建立数组中数字和出现次数的映射，判断是否大于1。
1 class Solution { 2 public: 3 bool containsDuplicate(vector<int>& nums) { 4 int len = nums.size(); 5 unordered_map<int, int> m; 6 7 for (int i = 0; i < len; i++) { 8 if(++m[nums[i]] > 1) { 9 return true; 10 } 11 } 12 13 return false; 14 } 15 };转载于:https://www.cnblogs.com/VickyWang/p/6012319.html
相关资源：数据结构—成绩单生成器