PAT甲级 1113

mac2022-06-30  77

PAT甲级 1113

题目 Integer Set Partition解析代码

题目 Integer Set Partition

Given a set of N (>1) positive integers, you are supposed to partition them into two disjoint sets A​1​​ and A​2​​ of n​1​​ and n​2​​ numbers, respectively. Let S​1​​ and S​2​​ denote the sums of all the numbers in A​1​​ and A​2​​ , respectively. You are supposed to make the partition so that ∣n​1​​ −n​2​​ ∣ is minimized first, and then ∣S​1​​ −S​2​​ ∣ is maximized. Input Specification: Each input file contains one test case. For each case, the first line gives an integer N (2≤N≤10​5​​ ), and then N positive integers follow in the next line, separated by spaces. It is guaranteed that all the integers and their sum are less than 2​31​​ . Output Specification: For each case, print in a line two numbers: ∣n​1​​ −n​2​​ ∣ and ∣S​1​​ −S​2​​ ∣, separated by exactly one space.

解析

将给出的数据分成两组,输出两组最小个数之差,输出两组各自和之差的最大值。将原数据排序,前一半为n1,后一半为n2;

代码

#include<bits/stdc++.h> #include<string> #define INF 1<<29 using namespace std; int n; int data[100005]; void pat1113() { cin >> n; int sum1 = 0, sum2 = 0; for (int i = 0; i < n; ++i) { cin >> data[i]; } sort(data, data + n); for (int i = 0; i < n; ++i) { if (i < n / 2) { sum1 += data[i]; } else { sum2 += data[i]; } } if (n % 2 == 0) { cout << "0" << " " << abs(sum2 - sum1) << endl; } else { cout << "1" << " " << abs(sum2 - sum1) << endl; } } int main() { pat1113(); return 0; }
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