@Override
public boolean onKeyDown(
int keyCode, KeyEvent event) {
if (keyCode ==
KeyEvent.KEYCODE_BACK) {
exit();
return false;
}
return super.onKeyDown(keyCode, event);
}
private long exitTime = 0
;
public void exit() {
if ((System.currentTimeMillis() - exitTime) > 2000
) {
Toast.makeText(getApplicationContext(), "再按一次退出程序"
,
Toast.LENGTH_SHORT).show();
exitTime =
System.currentTimeMillis();
} else {
finish();
System.exit(0
);
}
}
转载于:https://www.cnblogs.com/xinmengwuheng/p/5832662.html