Problem Description
Calculate S(n). S(n)=13+23 +33 +......+n3 .
Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.
Output
For each case, output the last four dights of S(N) in one line.
Sample Input
1 2
Sample Output
0001 0009
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
__int64 n,sum;
while(cin>>
n)
{
n = n%
10000;
sum=((n*(n+
1)/
2)*(n*(n+
1)/
2))%
10000;
printf("I64d\n",sum);
}
return 0;
}
公式的话,可以用数学归纳法推。
转载于:https://www.cnblogs.com/LZYY/p/3322836.html