Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him? Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y. Note: if year Y is a leap year, then the 1st leap year is year Y.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each test case contains two positive integers Y and N(1<=N<=10000).
Output
For each test case, you should output the Nth leap year from year Y.
Sample Input
3 2005 25 1855 12 2004 10000
Sample Output
2108 1904 43236 Hint（We call year Y a leap year only if (Y%4==0 && Y0!=0) or Y@0==0.）水题，注意开始年如果也是瑞年的话，也要算一个：
#include<iostream> using namespace std; int main(){ int n,a,b,count; cin>>n; while(n--){ count=0; cin>>a>>b; while(count!=b) { a=a+0; if((a%4==0 && a%100!=0)||a%400==0) {count ++;} a++; } cout<<a-1<<endl; } return 0; }转载于:https://www.cnblogs.com/LZYY/p/3292503.html
