软工网络15结对编程练习

mac2022-06-30  28

 

一.结对编程成员:

叶金蕾(201521123085):http://www.cnblogs.com/yeei66/

张文博(201521123089):http://www.cnblogs.com/Abe1/

二.对原有程序分析:

选择博客:http://www.cnblogs.com/shizhuangde/p/6552441.html  代码https://coding.net/u/lhl1212/p/ArithmeticTest/git?public=true

 

百度脑图

 

 

三.改进现有代码:

 

我们发现当我们第一次运行程序的时候,计算出来的正确率结果是正确的,然后点击“继续”之后,他的正确题数rn会累加,导致正确率计算出错,所以,我们应该在显示正确率之后令“rn=0.0”,避免他的累加

四.代码展示:

语言:

public void setLanguage() { String[] choiceLanguage = { "简体中文", "繁体中文", "English" }; String language = (String) JOptionPane.showInputDialog(null, "请选择语言:\n", "Choice a language for client", JOptionPane.PLAIN_MESSAGE, new ImageIcon("icon.png"), choiceLanguage, "简体中文"); if (language == null) { System.exit(-1); } else { try { reader = new BufferedReader(new FileReader(new File("language/" + language + ".txt"))); String s; while ((s = reader.readLine()) != null) { tips.add(s); } reader.close(); } catch (IOException e) { e.printStackTrace(); } } }

 

运算:

private void DivideButtonActionPerformed(java.awt.event.ActionEvent evt) { operateCommand = "/"; op1 = Double.parseDouble(resultText.getText()); //System.out.println("op1="+op1); firstDigit = true; } private void MultiplyButtonActionPerformed(java.awt.event.ActionEvent evt) { operateCommand = "*"; op1 = Double.parseDouble(resultText.getText()); firstDigit = true; } private void SubtractButtonActionPerformed(java.awt.event.ActionEvent evt) { operateCommand = "-"; op1 = Double.parseDouble(resultText.getText()); firstDigit = true; } private void AddButtonActionPerformed(java.awt.event.ActionEvent evt) { operateCommand = "+"; op1 = Double.parseDouble(resultText.getText()); firstDigit = true; }

 

 

 

 

五.PSP:

 

转载于:https://www.cnblogs.com/Abe1/p/8645747.html

相关资源:JAVA上百实例源码以及开源项目
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