题目链接
https://www.patest.cn/contests/pat-b-practise/1084
思路 用字符串模拟
然后要注意一点 它是连续的 才并在一起
就比如说
d, d1, d111, d113, d11231, d112213111, …
比如 d11231 -> d112213111
是 1个d 2 个 1 1 个 2 1 个 3 1 个 1
然后 并在一起就是
d112213111
而不是 d1132131
AC 代码
#include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime> #include <iostream> #include <algorithm> #include <deque> #include <vector> #include <queue> #include <string> #include <map> #include <stack> #include <set> #include <numeric> #include <sstream> #include <iomanip> #include <limits> #define CLR(a) memset(a, 0, sizeof(a)) #define pb push_back using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef pair <int, int> pii; typedef pair <ll, ll> pll; typedef pair<string, int> psi; typedef pair<string, string> pss; const double PI = 3.14159265358979323846264338327; const double E = exp(1); const double eps = 1e-30; const int INF = 0x3f3f3f3f; const int maxn = 1e5 + 5; const int MOD = 1e9 + 7; string tran(string s) { int len = s.size(); string ans = ""; char c = s[0]; int num = 1; for (int i = 1; i < len; i++) { if (s[i] == c) num++; else { ans += c; ans += num + '0'; c = s[i]; num = 1; } } ans += c; ans += num + '0'; return ans; } int main() { string ans; cin >> ans; int n; cin >> n; for (int i = 1; i < n; i++) ans = tran(ans); cout << ans << endl; }转载于:https://www.cnblogs.com/Dup4/p/9433201.html
