题目链接
https://www.patest.cn/contests/gplt/L1-025
思路
注意 输入字符串B的时候 要用getline 因为 可能存在空格 然后就把字符串 转化成 数字 并且判断一下 范围和 是否含有非法字符 就可以了
AC代码
#include <iostream> #include <cstdio> #include <algorithm> #include <cmath> #include <deque> #include <vector> #include <queue> #include <string> #include <cstring> #include <map> #include <stack> #include <set> #include <cstdlib> #include <ctype.h> #include <numeric> #include <sstream> using namespace std; typedef long long LL; const double PI = 3.14159265358979323846264338327; const double E = 2.718281828459; const double eps = 1e-6; const int MAXN = 0x3f3f3f3f; const int MINN = 0xc0c0c0c0; const int maxn = 1e5 + 5; const int MOD = 1e9 + 7; int f(string s) { int len = s.size(); int i; int num = 0; if (s[0] == '0') return -1; for (i = 0; i < len; i++) { if (s[i] <= '9' && s[i] >= '0') num = num * 10 + (s[i] - '0'); else { return -1; } } return num; } int main() { string a, b; cin >> a; getchar(); getline(cin, b); int n = f(a); int m = f(b); if (n >= 1 && n <= 1000 && m >= 1 && m <= 1000) printf("%d + %d = %d\n", n, m, n + m); else if(n <= 1000 && n >= 1) printf("%d + ? = ?\n", n); else if (m <= 1000 && m >= 1) printf("? + %d = ?\n", m); else printf("? + ? = ?\n"); }转载于:https://www.cnblogs.com/Dup4/p/9433299.html
