练习题
一、元素分类
有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。即： {'k1': 大于66的所有值, 'k2': 小于66的所有值}
二、查找
查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。
li = ["alec", " aric", "Alex", "Tony", "rain"]
tu = ("alec", " aric", "Alex", "Tony", "rain")
dic = {'k1': "alex", 'k2': ' aric', "k3": "Alex", "k4": "Tony"}
三、输出商品列表，用户输入序号，显示用户选中的商品
商品 li = ["手机", "电脑", '鼠标垫', '游艇']
四、购物车
功能要求：
要求用户输入总资产，例如：2000显示商品列表，让用户根据序号选择商品，加入购物车购买，如果商品总额大于总资产，提示账户余额不足，否则，购买成功。附加：可充值、某商品移除购物车
?
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goods
=
[
{
"name"
:
"电脑"
,
"price"
:
1999
},
{
"name"
:
"鼠标"
,
"price"
:
10
},
{
"name"
:
"游艇"
,
"price"
:
20
},
{
"name"
:
"美女"
,
"price"
:
998
},
]
五、用户交互，显示省市县三级联动的选择
?
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dic
=
{
"河北"
: {
"石家庄"
: [
"鹿泉"
,
"藁城"
,
"元氏"
],
"邯郸"
: [
"永年"
,
"涉县"
,
"磁县"
],
}
"河南"
: {
...
}
"山西"
: {
...
}
}
答案：
#!usr/bin/evn python
# -*- coding:utf-8 -*-
#1
dic={'k1':[],'k2':[]}
li=[11,22,33,44,55,66,77,88,99,90]
for i in li:
if i>=66:
dic['k1'].append(i)
else:
dic['k2'].append(i)
print(dic)
#2
li = ["aleb", " aric", "Alex", "Tony", "rain"]
tu = ("alec", " aric", "Alex", "Tony", "rain")
dic = {'k1': "alex", 'k2': ' aric', "k3": "Alex", "k4": "Tony"}
for i in li:
a=i.strip()
if (a.startswith('a') or a.startswith('A')) and a.endswith('c'):
print(a)
for j in tu:
b=j.strip()
if b.startswith('a') or b.startswith('A') and b.endswith('c'):
print('b-'+b)
for v in dic.values():
d=v.strip()
#print(d,'-')
if (d.startswith('a') or b.startswith('A')) and b.endswith('c'):
print('d-'+d)
#3
li = ["手机", "电脑", '鼠标垫', '游艇']
# a={}
# for i,j in enumerate(li,1):
#
# a[i]=j
#
# num=int(input('blabla:'))
#
# print(a[num])
for i, j in enumerate(li, 1):
print(i, j)
while 1:
num = int(input('blabla:'))
if num > 0 and num <= len(li):
print(li[num - 1])
else:
print('null')
#4
total_money = int(input('请输入总金额: '))
picked_car = []
picked_money = 0
goods = [
{"name": "电脑", "price": 1999},
{"name": "鼠标", "price": 10},
{"name": "游艇", "price": 20},
{"name": "美女", "price": 998},
]
goods_name = []
goods_name_price = {}
for i in goods:
a = i['name']
b = i['price']
goods_name.append(a)
# print(a)
goods_name_price[a] = b
# print(goods_name_price)
for j, k in enumerate(goods_name, 1):
print(j, k)
while 1:
goods_num = input('请输入选中商品号，付款请输入【购买】： ')
try:
goods_num = int(goods_num)
except ValueError:
goods_num = '购买'
try:
picked_car.append(goods_name[goods_num - 1])
picked_money += goods_name_price[goods_name[goods_num - 1]]
except TypeError:
pass
print(picked_money)
print(picked_car)
if goods_num == '购买' and total_money >= picked_money:
print('购买成功，谢谢惠顾')
break
elif goods_num == '购买' and total_money < picked_money:
user_choice = input('您的资金不足，请【充值】或者【移除】购物车内一些商品：')
if user_choice == '充值':
print('当前余额：' + total_money)
total_money += int(input('请输入总金额: '))
print('充值后金额：' + total_money)
continue
elif user_choice == '移除':
while 1:
print(picked_car)
del_choice = input('请输入要移除的商品,完事后输出【ok】继续付款：')
del picked_car[del_choice]
print(picked_car)
if del_choice == 'ok':
break
continue
#5
dic = {
"河北": {
"石家庄": ["鹿泉", "藁城", "元氏"],
"邯郸": ["永年", "涉县", "磁县"],
}
}
for i in dic:
print(i)
a=dic[i]
usip=str(input('输入省份: '))
for j in a:
print(j)
b=dic[i][j]
usip2=str(input('输入市: '))
for k in b:
print(k)
usip2=str(input('输入县: '))
转载于:https://www.cnblogs.com/ezway/p/6366421.html
