(define (sqrt-iter guess x) (if (good-enough? guess x) guess (sqrt-iter (improve guess x) x)))
(define (improve guess x) (average guess (/ x guess)))
(define (average x y) (/ (+ x y) 2))
(define (good-enough? guess x) (< (abs (- (square guess) x)) 0.001))
(define (sqrta x) (sqrt-iter 1.0 x))
(define (square x) (* x x))
(sqrta 9)
(sqrt 9)
我用的两个版本都是自带了sqrt函数,而不自带square函数.
所以把sqrt改成sqrta,然后自己实现square函数.
函数名里加了个问号,我还以为有三目表达式呢
转载于:https://www.cnblogs.com/R4mble/p/7878663.html
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