指向成员函数的指针

mac2022-06-30  22

// // main.cpp // testvoidmain // // Created by mac on 2019/4/11. // Copyright © 2019年 mac. All rights reserved. // 1.只有成员函数才能有const限定符 // 2.脑袋怎么总是混乱 // 3.在类内部定义指向函数的指针有点蠢? #include <iostream> using namespace std; template <class genType> class classf{ public: classf(){ } ~classf(){} genType fun1(genType &); genType (classf:: *p)(genType &)=&classf::fun1; }; template<class genType> genType classf<genType>::fun1(genType &a){ return a; } int main(int argc, const char * argv[]) { classf<int> cf,*q=&cf; int a=3; cout<<cf.fun1(a)<<endl; cout<<(cf.*(cf.p))(a)<<endl; cout << "Hello, World!\n"; return 0; }

运行结果

3 3 Hello, World! Program ended with exit code: 0

转载于:https://www.cnblogs.com/overlows/p/10690570.html

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