python实现单单链表

mac2022-06-30  26

# -*- coding: utf-8 -*- # @Time : 2018/9/28 22:09 # @Author : cxa # @File : node.py # @Software: PyCharm # 单向列表 # 数据元素区,下一个结点的链接区 # 尾节点指向的结点为空。 """ 表元素域 下一结点链接域 """ class Node: # 结点类 def __init__(self, elem): self.elem = elem self.next = None class SingLinkList(object): # 链表类 def __init__(self, node=None): self.__head = node def is_empty(self): """列表是否为空""" return self.__head == None def length(self): """结点的数目,到尾节点截止。需要一个游标、来记录当前的位置""" cur = self.__head """count记录数量,如果空链表也可以正确处理""" count = 0 """开始游标移动""" while cur: count += 1 cur = cur.next return count def travel(self): """遍历列表""" cur = self.__head while cur: print("当前的结点", cur.elem, end='') cur = cur.next def add(self, item): """从头部添加,头插法""" node = Node(item) node.next = self.__head self.__head = node def append(self, item): """从尾部添加,尾插法""" node = Node(item) if self.is_empty(): self.__head = node else: cur = self.__head while cur.next: cur = cur.next cur.next = node def insert(self, pos, item): node = Node(item) ''' 从指定位置添加 :param pos: 从0开始 :param item: :return: ''' if pos <= 0: self.add(item) elif pos > self.length(item) - 1: self.append(item) else: pre = self.__head # pre指前一个对象 count = 0 while count < pos - 1: count += 1 pre = pre.next # pre指向poss-1 node.next = pre.next pre.next = node def remove(self, item): """删除结点""" # pre.next=pre.next.next cur = self.__head pre = None while cur: if cur.elem == item: # 判断此节点是否是头节点 # 头节点 if cur == self.__head: self.__head = cur.next else: pre.next = cur.next break else: pre = cur cur = cur.next def search(self, item): """查找结点是否存在""" cur = self.__head while cur: if cur.elem == item: return True else: cur = cur.next return False if __name__ == '__main__': # 测试下正确性 ll = SingLinkList() print(ll.is_empty()) print(ll.length()) ll.append(1) print(ll.is_empty()) print(ll.length()) ll.append(2) ll.append(3) ll.add(8) ll.append(4) ll.travel()

转载于:https://www.cnblogs.com/c-x-a/p/9721592.html

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