<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>项目后台管理系统</title><link rel="stylesheet" href="__PUBLIC__/css/login.css" /><script type="text/javascript" src="__PUBLIC__/js/jquery.min.js"></script><script type="text/javascript">function $(id){ return document.getElementById(id);}//验证姓名function checkname(){ var name=$("admin_name").value; if(name=='') { $('s1').innerHTML='姓名不能为空'; $('s1').style.color='red'; return false; } else { $('s1').innerText='ok'; $('s1').style.color='green'; return true; }}//验证密码function checkpwd(){ var password=$("password").value; if(password=='') { $('s2').innerHTML='密码不能为空'; $('s2').style.color='red'; return false; } else { $('s2').innerHTML='ok'; $('s2').style.color='green'; return true; } }//验证所有表单提交function checkall(){ if(checkname()&&checkpwd()) { return true; } else { return false; }}</script></head><body class="b"><div class="lg"><form action="__URL__/dologin" method="POST" οnsubmit="return checkall();"> <div class="lg_top"></div> <div class="lg_main"> <div class="lg_m_1"> <input name="admin_name" value="" class="ur" id="admin_name" οnblur="checkname();"/><span id='s1'></span> <input name="password" type="password" value="" class="pw" id="password" οnblur="checkpwd();"/><span id='s2'></span> </div> </div> <div class="lg_foot"> <input type="submit" value="Login In" class="bn" /></div></form></div></body></html>
转载于:https://www.cnblogs.com/shaohuixia/p/5506692.html
相关资源：php js实现的拖动滑块验证码验证表单操作示例【附源码下载】