树型数据处理

mac2022-06-30  23

逐级汇总示例(循环逐级累计法)–邹老大. Create TABLE tb(ID int PRIMARY KEY,PID int,Num int) Insert tb Select 1,NULL,100 UNION ALL Select 2,1   ,200 UNION ALL Select 3,2   ,300 UNION ALL Select 4,3   ,400 UNION ALL Select 5,1   ,500 UNION ALL Select 6,NULL,600 UNION ALL Select 7,NULL,700 UNION ALL Select 8,7   ,800 UNION ALL Select 9,7   ,900 GO

–计算的存储过程 Create PROC p_Calc AS SET NOCOUNT ON DECLARE @Level int SET @Level=1

Select ID,PID,SUM_Num=Num, Level=CASE WHEN EXISTS(Select * FROM tb Where PID=a.ID) THEN 0 ELSE 1 END INTO # FROM tb a

WHILE @@ROWCOUNT>0 BEGIN SET @Level=@Level+1 Update a SET Level=@Level, SUM_Num=ISNULL(a.SUM_Num,0)+ISNULL(b.SUM_Num,0) FROM # a,( Select aa.PID,SUM_Num=SUM(aa.SUM_Num) FROM # aa,(Select DISTINCT PID FROM # Where Level=@Level-1)bb Where aa.PID=bb.PID AND NOT EXISTS( Select * FROM # Where PID=aa.PID AND Level=0) GROUP BY aa.PID )b Where a.ID=b.PID END Select a.*,b.SUM_Num FROM tb a,# b Where a.ID=b.ID GO

–调用存储过程进行计算 EXEC p_Calc /*–结果 ID          PID         Num         SUM_Num —————- —————— ——————- ——————– 1           NULL       100         1500 2           1           200         900 3           2           300         700 4           3           400         400 5           1           500         500 6           NULL       600         600 7           NULL       700         2400 8           7           800         800 9           7           900         900 –*/

逐级汇总示例(用户定义函数法) — 邹老大 Create TABLE tb(ID int PRIMARY KEY,PID int,Num int) Insert tb Select 1,NULL,100 UNION ALL Select 2,1   ,200 UNION ALL Select 3,2   ,300 UNION ALL Select 4,3   ,400 UNION ALL Select 5,1   ,500 UNION ALL Select 6,NULL,600 UNION ALL Select 7,NULL,700 UNION ALL Select 8,7   ,800 UNION ALL Select 9,7   ,900 GO

–得到每个节点的编码累计 Create FUNCTION f_id() RETURNS @t TABLE(ID int,Level int,SID varchar(8000)) AS BEGIN DECLARE @Level int SET @Level=1 Insert @t Select ID,@Level,’,'+CAST(ID as varchar)+’,’ FROM tb Where PID IS NULL WHILE @@ROWCOUNT>0 BEGIN SET @Level=@Level+1 Insert @t Select a.ID,@Level,b.SID+CAST(a.ID as varchar)+’,’ FROM tb a,@t b Where a.PID=b.ID AND b.Level=@Level-1 END RETURN END GO

–调用函数实现实现累计 Select a.ID,a.PID,a.Num,SUM_Num=SUM(b.Num) FROM tb a,f_id() a1, tb b,f_id() b1 Where a.ID=a1.ID AND b.ID=b1.ID AND b1.SID LIKE a1.SID+’%’ GROUP BY a.ID,a.PID,a.Num /*–结果 ID          PID         Num         SUM_Num —————- —————— ——————- ——————– 1           NULL       100         1500 2           1           200         900 3           2           300         700 4           3           400         400 5           1           500         500 6           NULL       600         600 7           NULL       700         2400 8           7           800         800 9           7           900         900 –*/

转载于:https://www.cnblogs.com/Gaojier/archive/2010/04/08/2783619.html

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