在写入到csv的时候我的日期格式出现了问题,只显示格式为:2011/06/05 12:02。导致我的秒数不存在了,所以在时间的后面都要加上chr(1)来得到正确的格式
csv读数据:
[php] view plain copy print ? $file = fopen($filename, 'w') or die('打开文件失败'); //读数据 $file = fopen($filename, 'r'); while ( $val = fgetcsv($file) ){ print_r($val); }fclose($file); $file = fopen($filename, 'w') or die('打开文件失败'); //读数据 $file = fopen($filename, 'r'); while ( $val = fgetcsv($file) ){ print_r($val); } fclose($file);csv的下载:
[php] view plain copy print ? $data = array( array('qq号','登录时间','名称'), array('123456','2012-08-21 15:21:10'.chr(1),'我是来测试的'), array('56788','2012-08-21 18:21:20 '.chr(1),'test测试数据'), array('321789','2012-08-21 11:21:25 '.chr(1),'HELLO') ); //下载功能 $date = time(); header("Content-Type: text/csv"); header("Content-Disposition: attachment; filename=".$date.".csv"); header('Cache-Control:must-revalidate,post-check=0,pre-check=0'); header('Expires:0'); header('Pragma:public'); foreach ( $data as $val ){ echo implode(",", $val)."\n"; } ----------------------------------------------------------------------------<?php$filename = "./creattest.csv"; //读数据 $file = fopen($filename, 'r'); $prex = "linpre";while ( $val = fgetcsv($file) ){ print_r($val); echo "<hr/>"; $val_list[] = $val;}$val_list[0][0] = $prex.$val_list[0][0];$val_list[1][0] = $prex.$val_list[1][0];echo $val_list[0][0]."------------";$file = fopen($filename, 'w'); foreach ( $val_list as $list ){ if( false === fputcsv($file, $list) ){ die('写入数据失败'); }}fclose($file);
转载于:https://www.cnblogs.com/alex-13/p/4014250.html
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